Question
Solution
SQL
SELECT
class_A.id,
class_A.name,
class_A.Marks,
class_B.address,
class_B.age
FROM class_A
NATURAL JOIN class_B;
4/4 test cases passed
No hidden test cases
SELECT
class_A.id,
class_A.name,
class_A.Marks,
class_B.address,
class_B.age
FROM class_A
NATURAL JOIN class_B;
4/4 test cases passed
No hidden test cases